A wheel of mass 2 kg and radius 10 cm is rotating about its axis at an angular velocity of 2 π π rad/s. The force that must be applied tangentially to the wheel to stop it in 5 revolutions is
Text Solution
Verified by ExpertsThe correct answer is:
D
Moment of inertia of wheel about its axis,
I = 
= 
= 0.01 kg-m 2
Now angular displacement, Δ Δ θ θ = 2 π π n = 2 π π × × 5 = 10 π π rad
∴ ∴ Angular retardation required, α α = 
= π π /5 rad/s 2
∴ ∴ Torque required τ τ = I α α ⇒ ⇒ FR = I α α
∴ ∴ F = 
= 
= 2 π π × × 10 − − 2 N
Hence is correct choice
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